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Nezavi [6.7K]
3 years ago
10

3

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

problem

confusion

Step-by-step explanation:

hope it helps

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(5x)/7 - x/14 = 9/7 solve for the unknown value this is a linear equation​
Ahat [919]

Step-by-step explanation:

\longmapsto \rm \dfrac{5x}{7} - \dfrac{x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{10x + x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{11x}{14} = \dfrac{9}{7} \\

→ 11x(7) = 14(9)

→ 77x = 126

→ x = 126 ÷ 77

→ x = 1.63

7 0
3 years ago
What is the sum of 5 feet 9 inches and 12 feet 3 inches
mestny [16]
5 ft + 12 ft = 17 ft 

<span>9 in + 3 in = 12 in = 1 ft </span>

<span>17 ft + 1 ft = 18 ft
</span>hope this helps
6 0
2 years ago
Read 2 more answers
What is the degree of the monomial?<br> 3.25 + 2x2 - y+3
disa [49]

Answer:

5

Step-by-step explanation:

The degree is just the number with the highest power. In this case, it is 3^5. Therefore, 5 is the degree.

If this helps please mark as brainliest

8 0
2 years ago
Find the value of x then classify the triangle​
butalik [34]
3.)

180-90-59=x
X=31

4.)

180-73-79=x
X=28
4 0
3 years ago
*Find the area of the figure below. Use 3.14 for pi.<br><br> Area= square inches
alex41 [277]

Answer:

100.26

Step-by-step explanation:

You would find the area of the semi circles on either side of the rectangle by plugging the diameter into the formula for the area of a circle. Then you would add that to the are of the rectangle.

This is what that would look like:

1. Divide 6 (the diameter) by 2 because r=\frac{1}{2} d

r=\frac{1}{2} 6

r=3

2. plug into the formula A=\pi r^{2}

A=\pi 3^{2}

3. square the 3

A=\pi 9

4. multiply 9 by 3.14 (pi)

A=28.26

This means the area of both the semi circles added together would equal 28.26

Then you would use the formula A=lw to find the area of the rectangle

1. plug in the numbers given

A= 12 · 6

2. solve

A=72

Then add the area of the semicircles to the area of the rectangle

A=28.26+72

to get the area of the entire figure:

A=100.26

3 0
3 years ago
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