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3 years ago

Simplified product ?

Mathematics

1 answer:

mel-nik [20]3 years ago

5 0

Answer:

Last choice is correct.

Step-by-step explanation:

$\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)$

$\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)$

$\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}$

$2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

Hence final answer is $10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

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2 years ago

Why isn’t the maximum ACT score (36) at the 100th percentile?

irga5000 [103]

Answer and Explanations

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3 years ago

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miv72 [106K]

<h3>Hello there!</h3>

Your question asks to find what was the size of the population in 2017

<h3>Answer: 6,721</h3>

In order to solve this problem, we're going to need to use the given information in the question in order to find the population in 2017.

Key information:

In 2010, population was 6500

In 2014, population increased by 10% from 2010

In 2017, population decreased by 6% from 2014.

With the information above, we can solve the problem.

We're going to start with 6500 as our starting population.

We know that the population increased by 10% in 2014, so we would multiply 6500 by 1.10.

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The population in 2014 was 7,150.

We know that in 2017, the population decreased by 6% from the population in 2014. So we would find how much 6% is from 7,150 and then subtract that number.

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When you're done solving, you sohuld get 6,721.

The population in 2017 would be 6,721.

<h3>I hope this helps!</h3><h3>Best regards, MasterInvestor</h3>

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3 years ago