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vekshin1
3 years ago
13

Simplified product ?

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

Last choice is correct.

Step-by-step explanation:

\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)

\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)

\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)

2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}

2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}

10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

Hence final answer is 10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}


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The perimeter of a triangle is 22cm. If one of the sides is 9cm,find the other sides if the area of the triangle is 20.976cm2 ​
Mekhanik [1.2K]

Answer:

Third side = 8.34 cm

Step-by-step explanation:

Given that,

The perimeter of a triangle, P = 22 cm

One side of a triangle, b = 9 cm

The area of the triangle, A = 20.976 cm²

The formula for the area of a triangle is given by :

A=\dfrac{1}{2}\times b\times h\\\\h=\dfrac{2A}{b}\\\\h=\dfrac{2\times 20.976}{9}\\\\h=4.66\ cm

Perimeter = Sum of all sides

9 cm + 4.66 cm + x = 22

x = 22 - 13.66

x = 8.34 cm

So, the third side of the triangle is 8.34 cm.

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2 years ago
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eimsori [14]

Answer:

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Step-by-step explanation:

The minimum would be 80. That means that the minimum sum would have to be 320 among the four numbers.

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now, we should see the maximum. It will be 89 so the sum of the four numbers cannot be anymore than 89*4 which is 356

So, 356-253=103

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Step-by-step explanation:

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