Given:
The equation of a circle is

A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is

Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is


We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.



Therefore, the gradient or slope of the tangent line l is
.
Answer:
With a vertex (h, k) at (0, 3) and given that a = -3, then the equation of this parabola in vertex form is as follows:
y = a(x - h)2 + k
y = -3(x - 0)2 + 3
y = -3x2 + 3
Step-by-step explanation:
Answer:
a. y^ -1 = e^x +2
Step-by-step explanation:
y = ln (x-2)
Exchange x and y
x = ln (y-2)
Solve for y
Raise each side with a base of e
e^ x = e^(ln(y-2)
e^x = y-2
Add 2 to each side
e^x +2 =y
9514 1404 393
Answer:
0.8
Step-by-step explanation:
The ratio of the first two terms is ...
1.2/1.5 = 4/5 = 0.8
That is also the ratio of successive adjacent terms.
0.96/1.2 = 0.768/0.96 = 0.8
The common ratio is 0.8.