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Answer:
3 cans of Brand B and 1 can of Brand A will minimize the daily cost
Step-by-step explanation:
<u>Approach</u>
Such a minimization problem can be approached a number of different ways:
- use the solver function of a spreadsheet program
- use an on-line Simplex Method calculator
- graph it
<u>Problem Formulation</u>
The problem is succinctly stated as ...
Minimize 0.8x +0.5y subject to 4x+y≥7, x+y≥4, 2x+4y≥12.
Additional implicit constraints are: x, y ≥ 0.
These constraints come from units of protein, carbohydrate, and fat, respectively.
<u>Solution</u>
Shown in the first two attachments are the solution using an on-line Simplex Method calculator. For that, and for the graphical solution in the third attachment, we use x and y to represent the numbers of cans of Brand A and Brand B, respectively.
The calculator says the optimal solution is ...
- 1 can of Brand A
- 3 cans of Brand B
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Since there are only two brand choices, we can use a 2-dimensional graph to display the inequalities. The <em>feasible region</em> is the area of overlap of the solutions to the three inequalities. The cost function is evaluated at each of the vertices of that region in order to find the one with minimum cost.
It can be convenient to graph the cost function as a line f(x, y) = constant, so that the slope of it can be compared to the boundaries of the feasible region. It is usually obvious visually which vertex will minimize the cost (put the cost line closest to the origin). In the attachment, the cost function is shown as a dashed line to differentiate it from the other boundary lines on the graph.
As with the on-line calculator, the graphical solution finds the optimum combination to be ...
(brand A, brand B) = (1 can, 3 cans)
