PWEASE HELP, AREA OF A TRAPEZOID

Mathematics

1 answer:

sdas [7]2 years ago

4 0

Answer:

34 m²

Step-by-step explanation:

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(7x^2-2) - (2x^2 - 5x + 3)

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(7x^2-2) - (2x^2 - 5x + 3)

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2 years ago

What is the remainder of 19 divided by 800

densk [106]

800 divided by 19
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80% of z is equal to 100. What is the value of x

Diano4ka-milaya [45]

Answer:

x = 125

80x = 100

----

100

80x = 10000

x = 10000

--------

x = 125

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2 years ago

List all the divisors (factors) of 891

larisa86 [58]

The factors of 891 are 1,3,9,11,27,33,81,99,297,891

Because
1 x 891,
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9 x 99,
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27 x 33,

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2 years ago

Find an equation of the tangent line to the bullet-nose curve y=|x|/sqrt(2−x^2) at the point (1,1) I think that square root is w

Mashcka [7]

$\bf y=\cfrac{|x|}{\sqrt{2-x^2}}\qquad \boxed{|x|=\pm\sqrt{x^2}}\qquad y=\cfrac{\sqrt{x^2}}{\sqrt{2-x^2}}\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{quotient~rule}{\cfrac{\frac{1}{2}(x^2)^{-\frac{1}{2}}\cdot 2x\cdot \sqrt{2-x^2}~~-~~\sqrt{x^2}\cdot \frac{1}{2}(2-x^2)^{-\frac{1}{2}}\cdot -2x}{(\sqrt{2-x^2})^2}}$

$\bf \cfrac{dy}{dx}=\cfrac{\frac{x\sqrt{2-x^2}}{\sqrt{x^2}}~~+~~\frac{x\sqrt{x^2}}{\sqrt{2-x^2}}}{2-x^2}\implies \cfrac{dy}{dx}=\cfrac{\frac{x(2-x^2)~~+~~x(x^2)}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}\\\\\\
\cfrac{dy}{dx}=\cfrac{\frac{2x\underline{-x^3+x^3}}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}\implies \cfrac{dy}{dx}=\cfrac{\frac{2x}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}$

$\bf \cfrac{dy}{dx}=\cfrac{2x}{\sqrt{x^2}\sqrt{2-x^2}(2-x^2)} \implies \boxed{\cfrac{dy}{dx}=\cfrac{2x}{|x|\sqrt{2-x^2}(2-x^2)}}
\\\\\\
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-------------------------------\\\\
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=2(x-1)\implies y-1=2x-2
\\\\\\
y=2x-1$

5 0

3 years ago