R = (2s - 6t + 5)/2
2R = 2s - 6t + 5
2s = 2R + 6t - 5
s = (2R + 6t - 5)/2
Do the crossing out method. so if it is 2.50 per pound for peaches, try A, 11 pounds. 2.50 times 11 is 27.5, and now we have the rest, 154 pounds as apples so we multiply it by 1.75 which is 269.5, we add them up and we dont get 337.50, so we try out b, 18 times 2.5 is 45 so we still have 147 pounds left for apples, multiply it by 1.75 which is 257.25 and if we add up 45 and 257.25 we dont get 337.5 so now we try c which is 65, multiply it by 2.5 its 162.5 and we have 100 pounds of apples left. we do the same and we get 175, 175 plus 162.5 is 337.5 so C/3 is the correct answer
A. Well she starts with 24 buns. She ate 1/2 half of a bun leaving 23 1/2 buns left. Then she gave her mother and father a bun each so you do 23 1/2 - 2 which gets you 21 1/2 buns. So the total number of buns that she has left is 21 and 1/2 buns.
Answer:
Neighborhood Q appears to have a bigger family size
Step-by-step explanation:
Mean = the sum of all data values divided by the total number of data values
Number of families in Neighborhood Q = 9
Mean family size of Neighborhood Q:
= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9
= 35 ÷ 9
= 3.888888...
Number of families in Neighborhood S = 9
Mean family size of Neighborhood S:
= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9
= 27 ÷ 9
= 3
The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.
a. 9:00 AM is the 60 minute mark:
b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is
c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is
The probability of doing so for at least 2 of 5 days is
i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.
d. Integrate the PDF to obtain the CDF:
Then the desired probability is
