Answer:
0.93
Step-by-step explanation:
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Given.


Take the second equation and subtract 2y to both sides.


Substitute x into the first equation and simplify.




Invert.

Substitute Y into your second equation.



Add -6 to both sides.


Answer:
(6, -3)
Answer:
Step-by-step explanation:
Note that there are two scale models with each of ratio of 1/2 and 1/16 respectively.
For the first model, the dimension will be as follows:
Length/2 by width/2
94/2 by 50/2 = 47 feet by 25 feet.
For the second model, the dimension will be as follows:
Length/16 by width/16
The dimensions of the second model is 94/16 by 50/16 = 5.875 feet by 3.125 feet.
Since we are to solve for the area of the smallest scale model which is
5.875 feet by 3.125 feet.
Hence, area (A) = L× W
=5.875 × 3.125 feet.
= 18.359ft^2