Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.
<h3>How old is Dianna now?</h3>
Given that, in 3 years, Dianna will be 4 times as old as she was 33 years ago.
Let x represent the age of Dianna presently.
Dianna's age in 3 years time will be: x + 3
Dianna's age 33 years ago is: x - 33
Since in 3 years, she will be 4 times as old as she was 33 years ago.
x + 3 = 4( x - 33 )
We solve for x
x + 3 = 4x - 132
3 + 132 = 4x - x
135 = 3x
x = 135/3
x = 45
Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.
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Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
120 divided by 4 is w
Step-by-step explanation: