Answer:
Given
x+y+z=0
⟹x+y=−z
Cubing on both sides
(x+y) 3 =(−z) 3
⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3
⟹x 3 +y 3 +3xy(x+y)=−z 3
⟹x 3+y 3+3xy(−z)=−z 3
⟹x 3 +y 3−3xyz=−z 3
⟹x 3 +y 3 +z 3 =3xyz
Step-by-step explanation:
Hope it is helpful.....
<u>Answer:</u>
9. x = 12
10. x = 31
<u>Step-by-step explanation:</u>
9. Corresponding angles are equal, so technically you can move that (7x - 20) to be diagonal with the (4x + 16). Along with the corresponding angle, diagonal angles are equal to each other. Therefore you can set (7x - 20) equal to (4x + 16) to find x.
7x - 20 = 4x + 16
Solve
3x - 20 = 16
3x = 36
x = 12
Therefore x is equal to 12
<u>Check:</u>
4(12) + 16
= 64
7(12) - 20
= 64
10. All angles in a triangle have to add up to 180 degrees. Therefore, you can write your equation like this:
x + 2x + 25 + 2x = 180
Combine like terms
5x + 25 = 180
Solve
5x = 155
x = 31
Therefore, x = 31.
<u>Check:</u>
31 + 2(31) + 25 + 2(31) = 180
31 + 62 + 25 + 62 = 180
180 = 180
<em>I hope this helps!!</em>
<em>- Kay :)</em>
<em />
Answer:
8
Step-by-step explanation:
f(1)=7(1-1)+8
f(1)=7(0)+8
f(1)=0+8
f(1)=8
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)
So the value of the element in the position 
is 15
So the value of the element in the position 
is 14
Then with these two values you can determinate the result matrix.
