Match the graph with a rule.<br> A. Y= -2x <br> B. Y = x - 2<br> C. Y = -x <br> D. Y = 2

The angle between 0 and 2π in radians that is coterminal with the angle 41/6π in radians is?

Inessa05 [86]

Answer:

5π/6

Step-by-step explanation:

Subtract multiples of 2π until you find the angle in the desired range.

41π/6 -36π/6 = 5π/6

The angle 5π/6 is co-terminal with 41π/6.

3 0

4 years ago

Can someone help me with 5-9 please?!?!? Thank you

valina [46]

5 is 1!!!!!!

Step-by-step explanation:

im sorry i dont know the others

3 0

2 years ago

I guess u have to find the area

Nesterboy [21]

18
Because 6•3= 18
Hope this helped

7 0

4 years ago

Read 2 more answers

These prisms are similar. find the volume of the larger prism in decimal form. a=5 v=300 a=6 v=[?]

zepelin [54]

Answer:

Step-by-step explanation:

When we divide congruent sides of similar solids or plane figures we get the linear scale factor.

The square of the linear scale factor gives the area scale factor while it's cube gives the volume scale factor.

In this question, the linear scale factor will be 6/5

since we are asked to find the volume we cube the linear scale factor.

(6/5)³=216/125

to get the volume of the larger prism we multiply the volume of the smaller by the V.S.L as shown

(216/125)×300in³= 518.4in³

4 0

3 years ago

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0

3 years ago

Match the graph with a rule. A. Y= -2x B. Y = x - 2 C. Y = -x D. Y = 2 - x