f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
wait i think i did the wrong one brb
Answer:
0.0012
Step-by-step explanation:
0.0096/8=0.0012
Answer:
Step by step explaination:
Y=-3
-3=-1.5x
you substitiue y value, then you divide both sides by -1.5 and you get 2 for x.
(2,-3)
y=4.5
4.5=-1.5x
you substitute y value, then again you divide both sides by -1.5 and you get 3.
(3,4.5)
y=6
6=-1.5x
same thing for this last one. then once again divide by -1.5 and you get -4.
(-4,6)
