2 years ago

What is a simple way to find 12 mod 7 + 12 mod 7 + 12 mod 7 + 12 mod 7?

1 answer:

3 0

12 ≡ 7 + 5 ≡ 5 (mod 7)

12 + 12 + 12 + 12 ≡ 4•12 ≡ 4•5 ≡ 20 ≡ 14 + 6 ≡ 6 (mod 7)

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Naily [24]

93/3=31 Answer is 31

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zaharov [31]

$\log_4(\log_42x)=1$

Take both sides as powers of 4:

$4^{\log_4(\log_42x)}=4^1\implies\log_42x=4$

Do it again:

$4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128$

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Alina [70]

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Step-by-step explanation: just took it

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julia-pushkina [17]

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Angelina_Jolie [31]

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