3 years ago

Write y=x^2+4x-5 in vertex form. Then identify the vertex.

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

7 0

the vertex form is (x+2)^2 - 9 and the vertex is (-2, -9)

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some numbers added to -11 is 37.divide this number by -12.then multiply by -8.what is the final number?

LUCKY_DIMON [66]

Since some number added to -11 is 37, we must do 37- (-11), which is 48. Then we check our work and find that 48+-11 is indeed 37. Now we divide 48 by -12, which is -4, multiply by -8 and get a final answer of 32.

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3 years ago

Jerilyn made 40 treats for her birthday.She gave 4 away to her family before taking the rest to school.What percent did Jerilyn

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3 years ago

Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

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3 years ago

Evaluate: ab – bc if a = 4, b = 3, and c = 2<br><br> ab - bc =

lorasvet [3.4K]

(4)(3)-(3)(2) = 12-6 = 6

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41 and 43 I hope this helps

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3 years ago