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PtichkaEL [24]
4 years ago
11

Find the missing number. a. 3 : 24 = ___ : 72 b. ___ : 18 = 5 : 9 c. 6: ___ = 36 : 36

Mathematics
2 answers:
sweet [91]4 years ago
7 0

A 9

B 10

C 6

Hope this helps;$

kotykmax [81]4 years ago
4 0

Answer:

a. 3:24 = 9:72.

b.  10:18 = 5:9.

c. 6:6 = 36:36.

Step-by-step explanation:

a.  72 / 24 = 3 so we multiply 3 by 3 to give 9.

b.  18/9 = 2  so we multiply 5 by 2 = 10.

c.  The answer is 6.

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What is a simple formula to solve a math sequence? Or a couple formulas if possible? Thanks!
-Dominant- [34]
2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2


the nth term is denoted by a_{n}
the first term is represented by a_{1}

for arythmetic sequences, the nth tem is
a_{n}=a_{1}(n-1)d where d=distance between each term

for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms

7 0
4 years ago
What is 18 ÷34
NeX [460]

Answer:

2/3 is the correct answer

5 0
3 years ago
Which of the following is the major negative aspect of crossover designs for research studies? A. Prohibitive cost B. Residual e
Zinaida [17]

Answer:

D. Incomplete randomization

Step-by-step explanation:

3 0
3 years ago
A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5
liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

Q(t) = Q(0)e^{rt}

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that Q(5730) = 0.5Q(0)

So

Q(t) = Q(0)e^{rt}

0.5Q(0) = Q(0)e^{5730r}

e^{5730r} = 0.5

\ln{e^{5730r}} = \ln{0.5}

5730r = \ln{0.5}

r = \frac{\ln{0.5}}{5730}

r = -0.00012

So

Q(t) = Q(0)e^{-0.00012t}

How old is the fossil?

This is t for which

Q(t) = 0.8Q(0)

So

Q(t) = Q(0)e^{-0.00012t}

0.8Q(0) = Q(0)e^{-0.00012t}

e^{-0.00012t} = 0.8

\ln{e^{-0.00012t}} = \ln{0.8}

-0.00012t = \ln{0.8}

t = -\frac{\ln{0.8}}{-0.00012}

t = 1860

The fossil is 1860 years old.

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3 years ago
Finding Distance in the Coordinate Plane!
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It is B. the differences are added together

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