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cricket20 [7]
3 years ago
10

Two children weighing 17 and 20 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. wh

ere on the seesaw should a 10-kilogram child sit in order to achieve equilibrium?
Mathematics
1 answer:
Ainat [17]3 years ago
4 0

In order to achieve an equilibrium some of momentum should be zero about the axis of rotation.

Suppose, the 10-kilogram child is placed X meters away from the axis of rotation.

Now, according to the question

17x2+10X-20x2=0

X=0.6m

Child should sit 0.6m away from the axis of rotation towards 17 Kg child.




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If alpha and beta are the zeroes of the polynomial f(x)= xsquare -8x +gamma such that alpha - beta = 2 find the value of gamma.
Komok [63]

Answer:

Γ = 15

Step-by-step explanation:

Given

f(x) = x² - 8x + Γ

with a = 1, b = - 8 and c = Γ , then

sum of zeros α + β = - \frac{b}{a} = - \frac{-8}{1} = 8

product of zeros = αβ = \frac{c}{a} = Γ

Given α - β = 2 , then

(α - β)² = 2²

α² - 2αβ + β² = 4 → (1)

and

(α + β)² = 8²

α² + 2αβ + β² = 64 → (2)

Add (1) and (2) term by term

2α² + 2β² = 68 ( divide through by 2 )

α² +β² = 34

Substitute α² + β² = 34 into (1)

34 - 2αβ = 4 ( subtract 34 from both sides )

- 2αβ = - 30 ( divide both sides by - 2 )

αβ = 15

Now

αβ = Γ = 15

Thus

f(x) = x² - 8x + 15

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snow_tiger [21]

Answer:

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Step-by-step explanation:

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