Find comon factors
300m^2=2*2*3*5*5*m*m
120m=2*2*2*3*5*m
180=2*2*3*3*5
GCF=2*2*3*5=60
factor out 60
60(5m²+2m+3)
answer is last one
Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
Answer:
351 adults and 275 students
Step-by-step explanation:
We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 626 tickets were purchased, then s+a=626.
We also know that 74 fewer student tickets then adult tickets. So s+76=a, the number of student tickets plus 76 will be the number of adult tickets.
We will solve by substituting one equation into the other. We substitute a=76+s into s+a=626. Simplify and isolate the variable a.
s+a=626
s+76+s=626
2s+76=626
2s+76-76=626-76
2s=550
s=275
This means that 275 students attended and 351 adults attended since 275+351=626.
