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otez555 [7]
3 years ago
6

When using the given diagram to determine the area of the pentagon by decomposition, which statements are correct?:

Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

Options (B) and (E)

Step-by-step explanation:

Area of ΔABC = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(14)(6)

                        = 42 in²

Area of trapezoid ADEC = \frac{1}{2}(b_1+b_2)h

[Here, b_1 and b_2 are the parallel sides and 'h' is the height of the isosceles trapezoid given]

= \frac{1}{2}(10+14)(8)

= 96 in²

Area of the pentagon = Area of triangle ABC + Area of trapezoid ADEC

                                    = 42 + 96

                                    = 138 in²

Therefore, Options (B) and (E) are the correct options.

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Answer:

23 degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line is 180°

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x = 52/4

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= 23 degrees

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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
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