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3 years ago

Help please I'm really confused I will mark a brainliest for correct answer

Mathematics

2 answers:

rosijanka [135]3 years ago

6 0

So first, you have to know Pythagorean theorem. First, you have to know the equation “(a^2)+ (b^2)=c^2”
It’s the first two legs squared equals the hypotenuse squared.
So the first leg, 12, squared is 144. The second leg, 16, squared is 256. 144+256= 400. Now, we only have 1 more step' which is finding the square root of 400. 20 × 20 = 400, so the length of the missing measure is the 4th answer, 20 yd.

max2010maxim [7]3 years ago

5 0

Easy do 12 times 16 divided by two = 96

answer=96

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You make $10 on the first day, $20 on the second day, $40 on the third day, $80 on the fourth day, and so on. What is your total

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The answer to this question is 5,120 you have to multiply by 2

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2 years ago

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2 years ago

1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us

kobusy [5.1K]

Because t is given in years and 1.08 = 1 + 0.08, the annual percent increase
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = $\frac{1}{12} * 12 t$ 
and the properties of exponents to rewrite the
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6 0

2 years ago

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Guys answer this one only one more question left

Karo-lina-s [1.5K]

Answer:

336

Step-by-step explanation:

i hope i got it right

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2 years ago

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What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

Given sequence:

6, 20, 40, 66, 98, 136, ...

Calculate the first differences between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the second differences:

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the second differences are the same, the sequence is quadratic and will contain an n² term.

The coefficient of the n² term is half of the second difference.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences between the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

1 year ago