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ollegr [7]
3 years ago
5

18 take away negative 10 is wha

Mathematics
2 answers:
Elodia [21]3 years ago
5 0
The question 18-(-10)=28

Ilya [14]3 years ago
3 0
18--10= 
the two negative signs make a plus so you simply have 18 + 10 which is 28
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Graphs that represent situations that may not have numerical values are Called?
vovikov84 [41]
Qualitative graphs.
7 0
3 years ago
A pack of 9 toilet rolls costs £4.23
OleMash [197]
 a)  9 toilet rolls cost $ 4.23
       1 toilet roll costs  $ x

          9x = 4.23 * 1
           x= 4.23 / 9
            x = 0.47
So in first case one toilet roll costs $ 0.47.

b) 4 toilet rolls cost $1.96
    1 toilet roll costs  $ x
     
    4x = 1.96 * 1
     x = 1.96 / 4
     x = 0.49
So in second case one toilet roll costs $ 0.49.

0.47 < 0.49
The toilet roll in first case is cheaper than the toilet roll in second case.

Hope this heps!


8 0
3 years ago
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
Kayla spent half of her weekly allowance on clothes. To earn more money her parents let her clean the oven for $4. What is her w
marysya [2.9K]
In this question, the first information that we get is that Kayla spent half of her weekly allowance in clothes. On cleaning the oven Kayla gets $4. Finally Kayla is left with $12.
Let us assume that the weekly allowance of Kayla = x
Amount of allowance saved after buying clothes = x/2
 Then we can go for the equation
x/2 + 4 = 12
x + (4 * 2) = 12 * 2
x + 8 = 24
x = 24 -8
   = 16
So we can now see that the weekly allowance of Kayla is $16
5 0
3 years ago
How much work must be done on a 1000-kg car to increase its speed from 1 m/s
yarga [219]

Answer:

w=f*d

f=ma

f=1000*10

f=10000

w=10000j

4 0
3 years ago
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