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Svet_ta [14]
4 years ago
11

Can someone please help

Mathematics
1 answer:
jeka944 years ago
5 0

Answer:

* (-5, 29)

* (2,1)

* (4,-7)

* (-9,18)

* (1,8)

* (5,4)

Step-by-step explanation:

plug in the x-values where the x is for the first 3. instead of it being -x change it to -1 then plug in the x-value

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An ice skater skates completely around the two circles shown in the diagram. Each circle has a diameter of 20 meters. What is th
Alchen [17]
Answer : c.) 126 meters
6 0
3 years ago
I need to show the work. Please help
Romashka-Z-Leto [24]

Answer:

x=5

Step-by-step explanation:

it all adds up to 180 so set (9x+2)+133=180

-133=-133

47

9×5=45+2=47=47

5 0
3 years ago
Read 2 more answers
Tori bought 24 candy bars for 69 cents each. She used partial products to find the total cost in cents. Which are NOT possible p
rewona [7]

Answer:

B. 36 C. 180 D. 240 E. 1,656

Step-by-step explanation:

Partial product is the multiplication of individual digit of a number in turn with each digit of the others where each digit maintains its place.

Using distributive property to multiply 24 × 69 to determine our partial products:

i.e.

24 × 69 = 24 × (60 + 9)

= (24 × 60) + (24 × 9)

= 60 (20 + 4) + 9(20 + 4)

So; we can have:

= (60 × 20) + (60 × 4) + (9 × 20) + (9 × 4)

= 1200 + 240 + 180 + 36  

= 1656

6 0
3 years ago
determine the price and quantity for which revenue is maximised given a firm demand function of a particular commodity to be (12
DerKrebs [107]
Demand
D(q)=(12-q)^(1/2)
Revenue,
R(q)=q*D(q)=q*sqrt(12-q)
At maximum revenue, 
R'(q)=0
where
R'(q)=sqrt(12-q)-q/[2(sqrt(12-q))]=0
Solve for q=8.
Hence, quantity=8, price=sqrt(12-q)=sqrt(12-8)=sqrt(4)=2


7 0
3 years ago
Solve Tan^2x/2-2 cos x = 1 for 0 < or equal to theta < greater or equal to 1.
mixer [17]

Answer:

x = theta = 0°

Step-by-step explanation:

Given the trigonometry function

Tan²x/2-2 cos x = 1

Tan²x-4cosx = 2 ... 1

From trigonometry identity

Sec²x = tan²x+1

tan²x = sec²x-1 ... 2

Substituting 2 into 1, we have:

sec²x-1 -4cosx = 2

Note that secx = 1/cosx

1/cos²x - 1 - 4cosx = 2

Let cosx. = P

1/P² - 1 - 4P = 2

1-P²-4P³ = 2P²

4P³+2P²+P²-1 = 0

4P³+3P² = 1

P²(4P+3) = 1

P² = 1 and 4P+3 = 1

P = ±1 and P = -3/4

Since cosx = P

If P = 1

Cosx = 1

x = arccos1

x = 0°

If x = -1

cosx = -1

x = arccos(-1)

x = 180°

Since our angle must be between 0 and 1 therefore x = 0°

4 0
3 years ago
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