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3 years ago

Please help me with this! Will give Brainliest for quickest answer!

1 answer:

riadik2000 [5.3K]3 years ago

7 0

1. A geometric sequence has a common ratio. You can find the ratio by dividing every number by its previous one. If it is consistent, then the series is geometric.
a: 8/1=8, 27/8=3.375
b: (-3/2)/3=-1/2, (3/4)/(-3/2)=-1/2
c. 7/4=1.75, 10/7=1.429
d. 20/25=0.8, 14/20=0.7

Choice b is the only one that has a common ratio, so it is a geometric series.

2. Every term is multiplied by 1/3, so the common ratio is 1/3. d is the answer.

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If a single 20 sided dice is tossed once what is the probability of rolling a 15 or 17

Alex17521 [72]

For a single 20 sided dice, a chance to get a certain number would be 1/20. For 2 numbers it will be a 2/20 chance, which can be simplified to a 1/10 chance that you will roll a 15 or a 17.

6 0

3 years ago

if each side of a square classroom is 25 feet then what is the perimeter of the room? what is the area of the floor of the room?

Svetllana [295]

Answer:

P = 100

Area = 625

Step-by-step explanation:

Area = s^2

sqrt(area) = sqrt(s^2)

area = 25*25

sqrt(25*25) = sqrt(s^2)

s = 25

P = 4*s

P = 4 * 25

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4 0

2 years ago

Question 2 A B C D E F G H

sleet_krkn [62]

Step-by-step explanation:

a. 2(y-8)

= 2y-16

b. 3(x-5)

= 3x-15

c.6(b-4)

= 6b-32

d.7(d-2)

= 7d-14

e.5(2-y)

= 10-5y

f.3(4-t)

= 12-3t

g.5(b-a)

=5b-5a

h.7(2-h)

= 14-7h

4 0

2 years ago

A building with a height of 14 m casts a shadow that is 16 m long while a taller building casts a 24 m long shadow. What is the

uranmaximum [27]

26 i am not really sure cuz what i did was 16-14= 2
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5 0

2 years ago

Read 2 more answers

Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ

Allisa [31]

Answer:

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

Step-by-step explanation:

There is a random binomial variable $X$ that represents the number of units come off the line within product specifications in a review of $n$ Bernoulli-type trials with probability of success $0.91$ . Therefore, the model is ${15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}$ . So:

$P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002$

$P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013$

$P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082$

$P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399$

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

8 0

2 years ago