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Anna11 [10]
3 years ago
8

Find sum (_6/3)+(_8/9)+7/3=

Mathematics
1 answer:
lidiya [134]3 years ago
8 0
-5/9 is the answer !!!
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Write the absolute value equations in the form x−b =c (where b is a number and c can be either number or an expression) that hav
erma4kov [3.2K]

Answer:

I hav this same question :(

Step-by-step explanation:

6 0
3 years ago
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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
3 years ago
A temperature of 3225 °F will melt platinum. Gold melts at a temperature of 1947.974 °F.
sertanlavr [38]

Questions like this ("how much higher is x than y?") are answered by computing the ratio of the two quantities.

In fact, for example, the answer to "how much higher is 10 than 5?" is 2, because 10:5 = 2, and indeed 10 is twice as much as 5.

So, we have

\dfrac{3225}{1947.974}\approx 1.65

So, the melting temperature of platinum is about one time and a half higher than the melting temperature of gold.

4 0
3 years ago
Edgar Elementary
kirza4 [7]

Answer:3333

Step-by-step explanation:

4 0
2 years ago
6x+6= x squared + x<br><br> How do I deal with the x squared when solving for x
lukranit [14]
I honestly think it has two solutions
X=-1
X=6
8 0
3 years ago
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