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Mice21 [21]
3 years ago
5

Find the equation of the line that passes through (-12, 3) and (6, -9). Write your answer in simplified slope-intercept form.

Mathematics
1 answer:
Travka [436]3 years ago
3 0

Answer:

y=-2/3x-5

Step-by-step explanation:

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Which equation is an identity?
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C. 3w + 8 - w = 4w - 2(w - 4)

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A jar contains quarters (worth $\$0.25$ each), nickels (worth $\$0.05$ each) and pennies (worth $\$0.01$ each). The value of the
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Given that ΔPQR is similar to ΔPTS, which statement MUST be true? A) m∠PST = m∠QPR B) m∠TPS = m∠RPQ C) m∠SPT = m∠PTS D) m∠PRQ =
galina1969 [7]

Answer:

The correct option is B.

Step-by-step explanation:

Two triangle are similar if their corresponding sides are in the same proportion or the corresponding angles are same.

It is given that the ΔPQR is similar to ΔPTS. It means all corresponding angles are same.

\angle R=\angle S

\angle Q=\angle T

\angle P=\angle P

Angle P can be defined as

\angle QPR=\angle TPS

\angle RPQ=\angle TPS

Therefore option B is correct.

\angle PST\neq\angle QPR

\angle SPT\neq\angle PTS

\angle PRQ\neq\angle PTS

Therefore option A, C and D are incorrect.

7 0
3 years ago
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Question 2
prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Calculating the area of the outer rectangle:</u>

Given

  • The length outer rectangle = l = 3x - 1
  • The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

A = wl

    = (5x + 2) (3x - 1)

    =5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)

     =5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1

      =15x^2+x-2

<u>Calculating the area of the inner rectangle:</u>

Given

  • The length inner rectangle = l = x + 7
  • The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

   = x(x+7)

   = x² + 7

<u>Calculating the area of the shaded region:</u>

As

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

  • The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

                                  = 15x² + x - 2 - (x² + 7)

                                   =  15x² + x - 2 - x² - 7

                                   = 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

4 0
3 years ago
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