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djverab [1.8K]
3 years ago
6

I need some help!! thank you if you know how to do it

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0
Hi there! The answer is A.

The expression consists of two parts.

Five times x..., which we can express as
5x (because this means 5*x, thus five times x)

...is sixty, which we can express as:
= 60

The answer is A. 5x = 60
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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
"
allsm [11]

Answer:

\boxed{\text{15.8 cords}}

Step-by-step explanation:

Step 1. Calculate the volume of the room

V = lwh =  5 yd × 5 yd × 3 yd = 75 yd³

Step 2. Convert cubic yards to cubic feet

3 ft = 1 yd

V = \text{75 yd}^{3} \times \left(\dfrac{\text{3 ft}}{\text{1 yd}} \right)^{3} = \text{2025 ft}^{3}

Step 3. Convert cubic feet to cords

128 ft³ = 1 cord

V = \text{2025 ft}^{3} \times \dfrac{\text{1 cord}}{\text{ 128 ft}^{3}} = \textbf{15.8 cords}\\\\\text{You could fit }\boxed{\textbf{15.8 cords}} \text{ of wood into the room.}

3 0
3 years ago
Can somebody help me find the mean,median, and mode
andrey2020 [161]

Answer:

so for the mean u add all the numbers on there and then divide it by 5 since there are 5 numbers on there so 78+84+100+78+81=421 now we divide 421 by 5 so 421÷5= 84!

now the median would be 100? and the mode is 78 since 78 is the number that showed the most!

3 0
3 years ago
Read 2 more answers
What number completes the following equation? 8×(40+7)=(8×?)+(8×7)​
morpeh [17]

Answer:

? = 40

Step-by-step explanation:

8×(40+7) is exactly the same as 8×40 + 8×7

6 0
3 years ago
Read 2 more answers
Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr
NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Distance between B(0, 5) and C(4, 2):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(0, 5) = (x_1, y_1)

C(4, 2) = (x_2, y_2)

BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}

BC = \sqrt{(4)^2 + (-3)^2}

BC = \sqrt{16 + 9} = \sqrt{25}

BC = 5 units

Distance between C(4, 2) and D(1, -2)

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(4, 2) = (x_1, y_1)

D(1, -2) = (x_2, y_2)

CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}

CD = \sqrt{(-3)^2 + (-4)^2}

CD = \sqrt{9 + 16} = \sqrt{25}

CD = 5 units

Distance between E(-2, -2) and F(-5, 2):

EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

E(-2, -2) = (x_1, y_1)

F(-5, 2) = (x_2, y_2)

EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}

EF = \sqrt{(-3)^2 + (4)^2}

EF = \sqrt{9 + 16} = \sqrt{25}

EF = 5 units

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0
3 years ago
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