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torisob [31]
3 years ago
10

$6.00+$8.00 = answer

Mathematics
2 answers:
Olin [163]3 years ago
7 0
$14.00 is the answer
aniked [119]3 years ago
4 0

Answer:

14,00

Step-by-step explanation:

14 bru

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Elza [17]

Answer:

20w+8

Step-by-step explanation:

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Can someone help me with this ​
Nataly_w [17]

Answer:

  b, e

Step-by-step explanation:

a, b) ordinarily, we claim the variable on the vertical axis is a function of the variable on the horizontal axis. By that claim, <em>temperature is a function of time</em>.

If the graph passed the horizontal line test (a horizontal line intersects in one place), then we could also say time is a function of temperature. The graph does not pass that test, so we cannot make that claim.

c) The graph has negative slope between 4:00 and 5:00. Temperature is decreasing in that interval, not increasing.

d) The graph has two intervals in which it is horizontal: 5:00-9:00 and 11:00-12:00. In those intervals it is neither increasing nor decreasing.

e) The graph shows a minimum in the interval 11:00-12:00. <em>The lowest temperature first occurs at 11:00</em>.

6 0
3 years ago
What is f(-3) if f(x) = 12x + 1] + 5?<br><br> Α. 0<br><br> B. 10<br><br> C. 12<br><br> D. -10
alexgriva [62]
Use the given functions to set up and simplify
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3 0
3 years ago
-6x+y=-2<br>x-3y=9 what is the solution set?
Anarel [89]
Mult. the 2nd eqn by 6 and then add this "new" equation to the 1st given eqn:

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--------------------
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3 0
3 years ago
HELP ON THIS PROBLEM!!<br><br> Solve the following 0deg&lt; x&lt; 360deg: cos x= cos 2x
blsea [12.9K]

Answer:

x=0^\circ,120^\circ,240^\circ,360^\circ

Step-by-step explanation:

<u>Use identities to set the equation up as a quadratic</u>

\cos x=\cos 2x;\:0^\circ \leq x \leq 360^\circ\\\\\cos x=2\cos^2 x-1\\\\0=2\cos^2 x-\cos x-1

<u>Make the substitution u=cos(x) and solve the quadratic</u>

<u />0=2u^2-u-1\\\\0=(2u+1)(u-1)

\displaystyle 0=2u+1\\\\0=2\cos x+1\\\\-1=2\cos x\\\\-\frac{1}{2}=\cos x\\\\120^\circ,240^\circ=x

0=u-1\\\\0=\cos x-1\\\\1=\cos x\\\\0^\circ,360^\circ=x

Hence, x=0^\circ,120^\circ,240^\circ,360^\circ

7 0
2 years ago
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