Answer:
1/11
Step-by-step explanation:
There are 7 gift card options so that makes it 7/77 which simplified is 1/11
<u>Answer:</u>
<u>Step-by-step explanation:</u>
Given equation to us is :-
So , here we can put different values of x in order to get different values of y .
Initial table given to us is ,
<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>
<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>
<u>Hence </u><u>the</u><u> </u><u>final</u><u> </u><u>table</u><u> </u><u>would</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

To solve this equation, first we have to use the distributive property to eliminate the parentheses on the left side of the equation.
If done correctly, your simplified equation should be
100,000 + 75,000x = 125,000
Next, we would subtract 100,000 from both sides, resulting in the equation
75,000x = 25,000
Finally, we would divide both sides of the equation by 75,000, resulting in your final answer of
x= 25,000/75,000
However, many mathematics teachers ask for fractional answers to be simplified. To simplify fractions, we first find the GCF of both numbers, and then divide both the numerator and the denominator by the GCF.
The GCF of 25,000 and 75,000 is 25,000.
So, in simplest form, your final answer is
x=1/3
Answer:
23x + 49
Step-by-step explanation:
4 (5x+15-2)+3x-3
subtract the numbers
4 (5x+13)+3x-3
distribute 4
20x+52+3x-3
23x+52-3
subtract
23x+49
Answer:
the SSS similarity theorem
Step-by-step explanation:
The triangles are not indicated as being right triangles (even though we know they are), so we cannot use the HL theorem.
The ratios of corresponding sides are the same, so the applicable theorem is ...
the SSS similarity theorem
__
3/(3+6) = 4/(4+8) = 5/15 = 1/3 . . . the ratio of shorter sides to corresponding longer sides.
_____
<em>Additional comment</em>
You recognize the smaller triangle as a 3-4-5 right triangle, and notice that the larger triangle is 3 times that size. If angle C were marked as the right angle it is, then the HL similarity theorem could also be used.