Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
b = 4.66666667
Step-by-step explanation:
The equation for finding the area of a triangle is
0.5b x h = a
b = base
h = height
a = area
So I calculated 14 divided by 6
And got 2.3333333
And since that number is half of the base, I multiplied it by 2
2.333 x 2 ≈ 4.66666667
A) Mr Chen was worth:
45,000/5 = 9,000
9,000 x 100 = 900,000
The answer is 900,00
You can also write this as an equation.
Answer:
RS 14400
Step-by-step explanation:
Given the following :
Principal sum = RS 40000
Rate = 2 paisa per 2 rupee per month
Interest at the end of 3 years
1 rupee = 100 paisa
2 Paisa per 2 rupee per month :
2/200 per month = 1 / 100 per month,
Hence rate = 0.01 = 1% monthly
Annual rate = 1% × 12 = 12 % = 0.12
Simple interest :
Principal × rate × time
40000 × 0.12 × 3
40000 × 0.36
= RS 14,400
Answer:
5.441683e+23
Step-by-step explanation:
Hope it helped brainiest plz
