Answer:
cout <<showpoint << x; is the statement which prints the decimal point, but without forcing scientific.
Explanation:
The showpoint function in c++ print the decimal point number without forcing scientific.The showpoint function set the showpoint format flag for the str stream in c++.
Following are the program in c++
#include<iostream> //header file
using namespace std; // namespace
int main() // main function
{
double x=90.67; // double variable
cout <<showpoint << x; // display x without forcing scientific
return 0;
}
Output
90.6700
Answer:
D to Protect sensitive data, Enterprise has certain security features and is mostly used in business settings.
Answer:
showProduct(int,double)
for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.
Explanation:
The code is
- <em>public static void showProduct (int num1, double num2){</em>
- <em> int product;</em>
- <em> product = num1*(int)num2;</em>
- <em> System.out.println("The product is "+product);</em>
- <em> }</em>
showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.
If showProduct( 10,10.0) is called the output will be 'The product is 100'.
Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is <em>product=num1*(int)num2</em>, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.
This is necessary in JAVA and many other programming languages as you <u>cannot</u><u> multiply two different datatypes</u> (here one is int and another is double). Either both of them should be of type int or both should be of type double.
Answer:
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
- In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
- In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
That's why the option "b" is correct.
