Answer:
The program to this question as follows:
Program:
//header file iostream
#include<iostream> //including file for use basic function
//using name space
using namespace std;
//main method
int main() //defining main method
{
int a[3][3]; //defining two dimension array
int x,y,sum=0; //defining variables
cout<<"Enter array elements: "<<endl; //message
for(x=0;x<3;x++) // for row
{
for(y=0;y<3;y++) //for column
{
cin>>a[x][y]; //input values from user.
}
}
//loop for calculting sum.
for(x=0;x<3;x++)
{
for(y=0;y<3;y++)
{
sum=sum+a[x][y];//add all elements
}
}
cout<<"Sum: "<<sum; //print sum.
return 0;
}
Output:
Enter array elements:
1
2
3
4
5
6
7
8
9
Sum: 45
Explanation:
In the above C++ programming language code first, a header file is included then the main method is declared, inside a main method 2D array that is "a[][]", and an integer variable is defined that are "i, j, and sum". In the next line for loop is used, this loop is used two times that can be described as follows:
- The first time it is used for inserting elements from user ends.
- The second time, it uses the sum variable to add all array elements. and in the last print function that is "cout" is used for print sum variable value.
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First addition, then division
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;