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siniylev [52]
2 years ago
14

Find different between manocots and dicots clarify with example​

Computers and Technology
1 answer:
Fantom [35]2 years ago
7 0

Answer:

hope it's help you..............

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Write a program that accepts a positive integer N as command-line argument, and outputs True if N is the square of some integer,
Ann [662]

Answer:

In Python:

N = int(input("Positive integer: "))

if N > 0:

   flag = False

   for i in range(1,N+1):

       if i * i == N:

           flag = True

           break

   print(str(flag))

else:

   print("Positive integer only")

   

Explanation:

N = int(input("Positive integer: "))

If the number is positive

if N > 0:

This initializes a boolean variable to false

   flag = False

This iterates from 1 to the input integer

   for i in range(1,N+1):

This checks if th number is a square of some integer

       if i * i == N:

If yes, flag is set to true

           flag = True

The loop is exited

           break

This prints either true or false, depending on the result of the loop

   print(str(flag))

If otherwise, that the number is not positive

<em>else:</em>

<em>    print("Positive integer only")</em>

3 0
3 years ago
to move from the second cell in the table in the accompanying figure back to the previous cell, press the ____ key(s)
Serhud [2]
I believe the answer is Shift + Tab
8 0
3 years ago
Using C#, declare two variables of type string and assign them a value "The "use" of quotations causes difficulties." (without t
stich3 [128]

Answer:

Let the two string type variables be var1 and var2.  The value stored in these two variables is : The "use" of quotations causes difficulties.

  • The variable which uses quoted string:

          string var1 = "The \"use\" of quotations causes difficulties.";  

  • The variable which does not use quoted string:

string var2 = "The " + '\u0022' + "use" + '\u0022' + " of quotations causes difficulties.";

  • Another way of assigning this value to the variable without using quoted string is to define a constant for the quotation marks:

const string quotation_mark = "\"";

string var2 = "The " + quotation_mark + "use" + quotation_mark + " of quotations causes difficulties.";

Explanation:

In order to print and view the output of the above statements WriteLine() method of the Console class can be used.

   Console.WriteLine(var1);

   Console.WriteLine(var2);

In the first statement escape sequence \" is used in order to print: The "use" of quotations causes difficulties. This escape sequence is used to insert two quotation marks in the string like that used in the beginning and end of the word use.

In the second statement '\u0022' is used as an alternative to the quoted string which is the Unicode character used for a quotation mark.

In the third statement a constant named  quotation_mark is defined for quotation mark and is then used at each side of the use word to display it in double quotations in the output.

8 0
3 years ago
1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
3 years ago
How does Technology impact any profession or occupation?
Brrunno [24]

Technology can create or dimish occupations.

Technology can also make the job easier

8 0
3 years ago
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