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svet-max [94.6K]
2 years ago
13

A(3,4) and B(-3,2) are pointd on a coordinate plane. find the coordinate of a points C on the x axis such that AC=BC​

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

Step-by-step explanation:

Here's the game plan. In order to find a point on the x-axis that makes AC = BC, we need to find the midpoint of AB and the slope of AB. From there, we can find the equation of the line that is perpendicular to AB so we can then fit a 0 in for y and solve for x. This final coordinate will be the answer you're looking for. First and foremost, the midpoint of AB:

and

Now for the slope of AB:

and

 So if the slope of AB is 1/3, then the slope of a line perpendicular to that line is -3. What we are finding now is the equation of the line perpendicular to AB and going through (0, 3):

and filling in:

y - 3 = -3(x - 0) and

y - 3 = -3x + 0 and

y - 3 = -3x so

y = -3x + 3. Filling in a 0 for y will give us the coordinate we want for the x-intercept (the point where this line goes through the x-axis):

0 = -3x + 3 and

-3 = -3x so

x = 1

The coordinate on the x-axis such that AC = BC is (1, 0)

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What is the true solution to the logarithmic equation?<br>log2 [log2(sqrt4x)]=1​
erastova [34]

Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

log₂2 =1

So we replace our 1 with log₂2

log₂[log₂(√4x)] = log₂2

log₂ on bothside will cancel each other.

We will be left with;

[log₂(√4x)] = 2

log = power of exponential

√4x = 2²

√4x = 4

Square bothside

(√4x)² = 4²

4X = 16

Divide bothside by 4

4x/4 = 16/4

x = 4

8 0
3 years ago
Read 2 more answers
The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th
Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.  

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is  

\large P(X>t) = e^{-t/10}

a)  

1 hour = 60 minutes, so the probability that you wait longer than one hour is

\large P(X>60)=e^{-6}=0.0025

b)

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

\large P(X\leq 10)=1-e^{-6}=0.9975

c)

We want x so that

P(X>x)=0.1

\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes

d)

We want P(X<x)=0.9

\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes

4 0
3 years ago
Please answer this question now
Sever21 [200]

Answer:

82 degrees

Step-by-step explanation:

Measure of arc ABC = 86*2 = 172 degrees.

Measure of arc DC = 360 - (145+172) = 360-317 = 43 degrees.

Measure of arc BCD = 121+43 = 164 degrees.

Measure of angle A = 164/2 = 82 degrees

8 0
3 years ago
Read 2 more answers
Ann Zoe and Jim bought a present for ben. Ann cooperated with $12 less than Zoe and $16 less than Jim. If the cost of the presen
sergeinik [125]

Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.

Ann (A): A

Zoe (Z): A = Z - 12 → Z = 12 + A

Jim (J): A = J - 16 → J = 16 + A

A + Z + J = 154

(A) + (12 + A) + (16 + A) = 154

3A + 28 = 154

3A = 126

A = 42

Ann (A): A = 42

Zoe (Z): Z = 12 + A = 12 + 42 = 54

Jim (J): J = 16 + A = 16 + 42 = 58

Answer: Ann=42, Zoe=54, Jim=58

6 0
3 years ago
PLSS HELP
Dmitry [639]

Answer:

$8,000

Step-by-step explanation:

Let the store earned $x in December.

Therefore,

Money spent to buy new inventory =\frac{1}{4} x

Remaining money = x - \frac{1}{4} x =\frac{3}{4} x

Money used to pay bills =\frac{1}{2} \times \frac{3}{4} x=\frac{3}{8} x

Money still left over = $3,000

Total money earned in December = \frac{1}{4} x+ \frac{3}{8} x+3,000

\therefore x= \frac{1}{4} x+ \frac{3}{8} x+3,000

\therefore x= \frac{2}{8} x+ \frac{3}{8} x+3,000

\therefore x= \frac{5}{8} x+ 3,000

\therefore x- \frac{5}{8} x=3,000

\therefore \frac{8x-5x}{8} =3,000

\therefore \frac{3x}{8} =3,000

\therefore x =3,000\times \frac {8}{3}

\therefore x =1,000\times 8

\therefore x =\$8,000

Thus, total money earned in December is $8,000.

3 0
3 years ago
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