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2 years ago

15

Can someone help me on this and explain what most of what to do

1 answer:

irina1246 [14]2 years ago

7 0

For number 11 think of them as decimals and1/2 is .5 and on 12 put them all in as decimals and figure it out and on 13 divide 1/4 and it will get you .25 and add the 6 and the rest all the same rules apply and you just have to figure out which one it is

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Question 10<br> Evaluate 122 – 3 [4 () – (18)].

tatuchka [14]

Answer:

here is the answer -(12)/(-3)

Step-by-step explanation:

PLEASE MARK BRAINILIEST!

4 0

3 years ago

Prove these identities <br>(i) secx cosecx - cotx = tanx<br>

brilliants [131]

Answer:

$(A)\frac 1 {cosx} \frac 1 {sin x} - \frac {cosx} {sin x} = \frac {sin x} {cosx} \\\\(B)\frac{1-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(C) \frac{(sin^2x + cos^2x)-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(D) \frac{sin^2x }{cos x sin x} = \frac {sin x} {cosx}\\\\(E)\frac {sin x}{cos x} = \frac {sin x}{cos x}$

In step A, you replace all trigonometric functions with their definitions in terms of sine and cosine.

In step B, you add the two together as you add fractions.

In step C, you replace 1 with the sum of the squares of sine and cosine.
In step D, you add the cosine terms together so they disappear.

In step E, finally, you divide numerator and denominator by $sin x$ .

3 0

2 years ago

How to figure it out

harkovskaia [24]

Have
.5x+.10y+.20z=380

8 0

2 years ago

Is this non-linear yes or no

Serjik [45]

It's linear and equation of the function is :

f ( x ) = 2x - 1

3 0

2 years ago

Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities. What i

Serjik [45]

Answer:

The scale used on his map is <u>150 miles : 2 inches</u>.

Step-by-step explanation:

Given:

Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities.

Now, to find the scale Ted used on his map.

The actual distance Ted know between two cities = 150 miles.

The distance on map between these cities = 2 inches.

So, to get the scale used on his map:

$\frac{The\ actual\ distance\ Ted\ know\ between\ two\ cities}{The\ distance\ on\ map\ between\ these\ cities}$

$=\frac{150\ miles}{2\ inches}$

$=150\ miles:2\ inches.$

Therefore, the scale used on his map is 150 miles : 2 inches.

5 0

2 years ago