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Andrej [43]
3 years ago
15

Can someone help me on this and explain what most of what to do

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0
For number 11 think of them as decimals and1/2 is .5 and on 12 put them all in as decimals and figure it out and on 13 divide 1/4 and it will get you .25 and add the 6 and the rest all the same rules apply and you just have to figure out which one it is
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136+12x=-4(1-2x) simplify
lawyer [7]

Answer:

x=-35

Step-by-step explanation:

136+12x=-4(1-2x)

136+12x=-4+8x

+4          +4

140+12x-12x=8x-12x

140/-4=-4x/-4

x= -35

8 0
3 years ago
Given: △ABC, m∠A=60°,<br> m∠C=45°, AB=9<br> Find: Perimeter of △ABC,<br> Area of △ABC
stellarik [79]

Answer:

Perimeter of ΔABC: \frac{27}{2} + \frac{9}{2} * \sqrt6 units

Area of ΔABC: \frac{81}{8}*\sqrt3 + \frac{243}{8} units

<u>Skills required: HS Geo, Special Triangles</u>

Step-by-step explanation:

1) The best option is to break down this triangle. Let's draw an altitude from Point B down to Segment AC. The point from the altitude that intersects AC is Point D. BD is the height of our triangle, AC is the base.

2) Angle A is 60 degrees, and since Angle BDA is 90 degrees, Angle ABD is 30 degrees. We can use the 30-60-90 degree right triangle property for the triangle BDA.

  • This states that if the side opposite the 30 degree angle is x, the side opposite the 60 degree angle is x*\sqrt3, and the side opposite the 90 degree angle is 2x.

AB is 9 units, and it is opposite the 90 degree angle. This means that 2x=9, x = \frac{9}{2} ==> This then means that AD, the segment opposite the 30 degree angle in this triangle is \frac{9}{2} units. Segment BD (the height) is \frac{9}{2} * \sqrt3.

3) Angle C is 45 degrees, and Angle BDC is 90 degrees, which means that Angle CBD is 45 degrees. We can use the 45-45-90 degree right triangle property for the triangle BCD.

  • This states that if the side opposite the 45 degree angle is x, the other side opposite a 45 degree angle is also x, but the hypotenuse (side opposite the right (90 degree) angle) is \sqrt{2}*x.

BD is \frac{9}{2} * \sqrt3, which means DC is the same. BC, which is the hypotenuse is BD multiplied by square-root-2, which is \frac{9}{2} * \sqrt6.

4) Area is \frac{1}{2}*b*h, the base (b) is AC (which is \frac{9}{2}+\frac{9}{2}*\sqrt3), the height is BD (\frac{9}{2}*\sqrt3). When multiple you will get \frac{81}{4}*\sqrt3 + \frac{243}{4}, then this multiplied by 1/2 is

\frac{81}{8}*\sqrt3 + \frac{243}{8} <--> this is the area!

5) Perimeter is just the sum of all side: 9 + \frac{9}{2} + \frac{9}{2} * \sqrt6 = \frac{27}{2} + \frac{9}{2} * \sqrt6 unit

6 0
3 years ago
What is the area of the figure?<br><br><br><br> 40 ft2<br> 84 ft2<br> 96 ft2<br> can't be determined
maxonik [38]
<span>80 ft^2 Looking at the figure, you can easily determine that it's made of two separate figures, a rectangle that's 2 feet by 16 feet, and a triangle that has sides of 16 feet, 10 feet, and 10 feet. The triangle can then be divided into two right triangles with a hypotenuse of 10 feet and one leg of 8 feet, so you can use the Pythagorean theorem to calculate the other leg (which is also the height of the large triangle mentioned above). That value is sqrt(10^2 - 8^2) = sqrt(100 - 64) = sqrt(36) = 6. So we now know that the large 16,10,10 triangle has a base of 16 and a height of 6. So let's calculate the area of the entire figure. A = 2*16 + 16*6/2 A = 32 + 16*3 A = 32 + 48 A = 80 So the area of the entire figure is 80 square feet.</span>
5 0
4 years ago
In which quadrant are the x-coordinates of a point negative? Choose all answers that are correct. A. I B. II C. III D. IV
Cerrena [4.2K]
That would be quadrants II and III
8 0
3 years ago
Read 2 more answers
Question is in the pic.
Andrews [41]

Answer is C as all other choices are even numbers therefore make the equation non-integer.

5 0
2 years ago
Read 2 more answers
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