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3 years ago

15

Can someone help me on this and explain what most of what to do

1 answer:

irina1246 [14]3 years ago

7 0

For number 11 think of them as decimals and1/2 is .5 and on 12 put them all in as decimals and figure it out and on 13 divide 1/4 and it will get you .25 and add the 6 and the rest all the same rules apply and you just have to figure out which one it is

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When h has the value 4, calculate 16-3h

azamat

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3 years ago

The sum of 30 times (1/3)^(n-1) from 1 to infinity

sergeinik [125]

Let

$S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}$

Then

$\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}$

and

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and as $n\to\infty$ , we end up with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32$

So we have

$\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45$

8 0

3 years ago