Plz help fast will mark the brainiest!!!

The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation

antiseptic1488 [7]

Answer:

$P(X>30000)=P(\frac{X-\mu}{\sigma}>\frac{30000-\mu}{\sigma})=P(Z-2)$

And we can find this probability using the complement rule and the normal standard distribution

$P(z>-2)=1-P(z$

Step-by-step explanation:

Let X the random variable that represent the starting salaries of individuals with a MBA of a population, and for this case we know the distribution for X is given by:

$X \sim N(40000,5000)$

Where $\mu=40000$ and $\sigma=5000$

We are interested on this probability

$P(X\geq 30000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(X>30000)=P(\frac{X-\mu}{\sigma}>\frac{30000-\mu}{\sigma})=P(Z-2)$

And we can find this probability using the complement rule and the normal standard distribution

$P(z>-2)=1-P(z$

6 0

3 years ago

The position (resp. velocity, resp. acceleration) at time t of a particle of mass m is c(t) (resp. v(t), resp. a(t)). Let F(x, y

sergey [27]

Answer:

(f(x, y, z), g(x, y, z), h(x, y, z))

Step-by-step explanation:

i think it is amswer

5 0

3 years ago

Congruent segments have the same________ Fill in the blank.

vodomira [7]

Length or measurement

4 0

3 years ago

I upped the steaks plz answer this, I will give brainiest

Bad White [126]

Answer:

$\displaystyle x = \frac{3}{4}$

Step-by-step explanation:

we are given that

$\displaystyle P = \left(x, - \frac{ \sqrt{7} }{4} \right)$

we want to figure out x

remember that,

In unit circle x coordinate is considered cos and y coordinate is considered sin

so in order to figure out x we should figure out the value of cos to do we can consider Pythagoras trig indentity

given by

$\displaystyle \sin ^{2} ( \theta) + { \cos}^{2} ( \theta) = 1$

we are given sin=-√7/4 thus

substitute:

$\displaystyle \left( - \frac{ \sqrt{7} }{4} \right) ^{2} + { \cos}^{2} ( \theta) = 1$

simplify square:

$\displaystyle \frac{7}{16} + \cos ^{2} ( \theta) = 1$

move left hand side expression to right hand side and change its sign:

$\displaystyle \cos ^{2} ( \theta) = 1 - \frac{7}{16}$

simplify Substraction:

$\displaystyle \cos ^{2} ( \theta) = \frac{9}{16}$

square root both sides:

$\displaystyle \cos ^{} ( \theta) = \pm\frac{3}{4}$

since in unit circle cos is x and P belongs to Q:IV negative cos isn't applicable

hence,

$\displaystyle x = \frac{3}{4}$

5 0

3 years ago

8.912.573 rounded to the ten-thousands is

bija089 [108]

Answer:

8.900.000

Step-by-step explanation:

7 0

3 years ago

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