Someone please answer my question!!! I'll add more points!!!

Standard form of the equation that goes through (3, -1) with a slope of -1, please!

11111nata11111 [884]

Answer:

x+y=2

Step-by-step explanation:

Standard Form: ax+by=c

For most convenience start with slope-intercept form: y=mx+b

1. -1 = -1(3)+b - solve for b

b=2

y= -1x+2 (slope-intercept form)

2. Now convert to standard form

Add 1x to both sides:

1x+y=2

7 0

3 years ago

1. Jeff writes comic strips for a local newspaper. The number of comic strips he creates is represented by the function f(x) = 3

Vaselesa [24]

1 ) f ( x ) = 3 x
He can write { 9, 12, 18, 21, 27 } comic strips.
2 ) f ( x ) = 5 x - 3
- 13 = 5 x - 3
5 x = - 10
x = -2, etc.
The domain is: { - 2 , - 1 , 0, 3, 4 }
3 ) f ( x ) = 2 x
It will take { 8, 20, 28, 32, 36 } hours.

4 0

4 years ago

Suppose the national mean annual salary for a school administrator is $91,000 a year. A school official took a sample of 25 scho

Gemiola [76]

Answer:

H0 : μ = 91000

H1 : μ ≠ 91000

Test statistic = - 2.594

Pvalue = 0.016

|Tcritical | = 2.064

Reject H0. We can conclude that the mean annual administrator salary in Ohio differs significantly from the national mean annual salary.

Step-by-step explanation:

The hypothesis :

H0 : μ = 91000

H1 : μ ≠ 91000

From the data given :

77600 76000 90700 97200 90700

101800 78700 81300 84200 97600

77500 75700 89400 84300 78700

84600 87700 103400 83800 101300

94700 69200 95400 61500 68800

Using calculator :

Sample mean, xbar = 85272

Sample standard deviation, s = 11039.23

Sample size, n = 25

The test statistic :

(xbar - μ) ÷ (s/√(n))

(85272 - 91000) / (11039.23/√(25)

Test statistic = - 5728 / 2207.846

Test statistic = - 2.594

The Pvalue : df = n - 1 = 25 - 1 = 24

Pvalue(-2.594, 24) = 0.0159

Decision region :

Reject H0 ; If Pvalue < α ;

α = 0.05

Using the critical value :

Decision region :

Reject H0 ; If Test statistic > |Tcritical;

Tcritical value at df = 24 ; α = 0.05 ;

|Tcritical | = 2.064

Hence,

We Reject H0 ; Since, |Test statistic| > |Tcritical|and conclude that mean salary depends differs

3 0

3 years ago

HELP I WILL GIVE BRAINLY THING

lana [24]

Answer:

The answer is A.

Step-by-step explanation:

Hope this helps.

4 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a

VMariaS [17]

(a) If $y(t)$ is the mass (in mg) remaining after $t$ years, then $y(t) = y(0) e^{kt}=100e^{kt}.$

$y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}$

(b) $y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}$

(c)
$100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}$

3 0

3 years ago