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scZoUnD [109]
3 years ago
11

WILL MARK BRAINLIEST

Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

135 students

Step-by-step explanation:

300*28%.     = 135

Jeez you could just use a calculator lol

PIT_PIT [208]3 years ago
7 0

Answer:

22%

Step-by-step explanation:

you subtract the both from the reading.

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A triangle has a perimeter of 72 units, and two of its sides measure x units and 3x units, respectively. Which inequality repres
blagie [28]

Answer:

x

Step-by-step explanation:

Given: Perimeter of triangle= 72 units

          Measure of one of the side= x units

          Measure of second side = 3x units

We know the perimeter of triangle is equal to sum of all sides.

Now, finding the possible value of x

forming an inequality to determine the value of x

Remember triangle has three sides, however, measure of only two sides are given.  

⇒ x+3x < 72\ units

⇒ 4x

Dividing both side by 4

⇒ x < 18

∴ The inequality to represents all possible values of x is x < 18

4 0
3 years ago
The original price of a vest for sale at a department store is $80. The store is having a 20%-off sale, and you have a coupon th
Sergeu [11.5K]

Answer:

$51.2

Explanation

80×80=6400÷100=$64

64×80=5120÷100=$51.2

7 0
3 years ago
Read 2 more answers
What is the perimeter?
aev [14]

Answer:

38

Step-by-step explanation:

9²+10² = 38

5 0
3 years ago
What is the slope of the line that passes through the points (-10, -8) and (−8,−16)? Write your answer in simplest form.
Leto [7]

Answer:y=-8 x=2

-8/2 or -4

Step-by-step explanation:

3 0
3 years ago
Mathematical Statistics with Applications Homework Help
photoshop1234 [79]

7.37:

a. <em>W</em> follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

\displaystyle \sum_{i=1}^n\left(\frac{Y_i-\mu}{\sigma}\right)^2

is chi-squared distributed with <em>n</em> d.f.. Here we have \mu=0 and \sigma=1.

b. <em>U</em> follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

\displaystyle \frac1{\sigma^2}\sum_{i=1}^n (Y_i-\overline Y)^2

is chi-squared distributed with <em>n</em> - 1 d.f..

c. <em>Y₆</em>² is chi-square distributed for the same reason as <em>W</em>, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then <em>U</em> + <em>Y₆</em>² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.

7.38:

a. Notice that

\dfrac{\sqrt 5 Y_6}{\sqrt W} = \dfrac{Y_6}{\sqrt{\frac W5}}

and see definition 7.2 for the <em>t</em> distribution. Since <em>Y₆</em> is normally distributed with mean 0 and s.d. 1, it follows that this random variable is <em>t</em> distributed with 5 degrees of freedom.

b. Similar manipulation gives

\dfrac{2Y_6}{\sqrt U} = \dfrac{\sqrt4 Y_6}{\sqrt U} = \dfrac{Y_6}{\sqrt{\frac U4}}

so this r.v. is <em>t</em> distributed with 4 degrees of freedom.

4 0
3 years ago
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