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atroni [7]
2 years ago
10

Use the relationship among the three angles of any triangle to solve. Two angles of a triangle have the same

Mathematics
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

51°,51°,78°

Step-by-step explanation:

The sum of angles in a triangle add up to 180°

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Will uses 3 1/4 ounces each of 5 different types to make fruit smoothies. How many ounces did he use
abruzzese [7]
3 1/4 ounces = 3.25 Ounces.

3.25 x 5 = 16.25 ounces (16 1/4 ounces)
3 0
3 years ago
Question #2:
Lesechka [4]

Answer:

If 4/8 cm = 25 miles

If 4.8 cm = 240 miles

If 48 cm = 2400

Step-by-step explanation:

4/8 x 50

4.8 x 50

48 x 50

I was unsure if there was a fraction bar or decimal. or if it was 48 so I gave all possibilities.

3 0
3 years ago
Solve 5c − c + 10 = 34. <br> −6 <br> 6 <br> 11 <br> −11
natima [27]

Subtract 10 and collect terms to get the variable term by itself on the left.

... 4c = 24

Divide by the coefficient of the variable, 4.

... c = 6

The appropriate choice is the second one:

... 6

_____

You don't actually have to sove the equation to find the right answer. You just need to see which answer works.

-6: 5(-6) -(-6) +10 = -14 ≠ 34

6: 5(6) -(6) +10 = 34 . . . . . . . this answer works (you can stop here)

11: 5(11) -(11) +10 = 54 ≠ 34

-11: 5(-11) -(-11) +10 = -34 ≠ 34

7 0
3 years ago
It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less t
zavuch27 [327]
<span>Let C denote the number of candidates they interview and E the number of employees they train.
</span>
<span>If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.
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If <span>it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.
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Company has less than <span>$95000, then 400C+3600E<95000.
</span>
Company <span>wants to spend at most 470 hours, then 20C+120E\le&#10; 470.
</span>
<span>You obtain the system of two inequalities:
</span>

\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le&#10; 470}} \right.  \\  \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le &#10;23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le &#10;94}} \right.
Then you can solve this system according to your demands.






3 0
3 years ago
Plz help me i dont even know how to start this can u also explain how to do it much appretciated
Sergeu [11.5K]
Ok did your teacher say anything about not being able to use negative numbers or fractions? If not can you use fractions or negative numbers.
4 0
3 years ago
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