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Daniel [21]
2 years ago
15

A spyware is trying to break into a system by guessing its password. It does not give up until it tries 1 million different pass

words. What is the probability that it will guess the password and break in if by rules, the password must consist of
Mathematics
1 answer:
Anettt [7]2 years ago
6 0

Answer:

Probability = 0.006033

Step-by-step explanation:

Given

Tries = 1000000

Required

Determine the probability of 6 different lower case letters <em>(Question continuation)</em>

<em />

There are 26 lower case letters.

The first can be any of letters 26

The second can be any of letters 26 - 1

The third can be any of letters 26 - 2

The fourth can be any of letters 26 - 3

The fifth can be any of letters 26 - 4

The sixth can be any of letters 26 - 5

Number of selection is:

Selection = 26 * (26 - 1) * (26 - 2) * (26 - 3) * (26 - 4) * (26 - 5)

Selection = 26 * 25 * 24 * 23 * 22 * 21

Selection = 165765600

The probability is:

Probability = \frac{Tries}{Selection}

Probability = \frac{1000000}{165765600}

Probability = 0.00603261472

<em></em>Probability = 0.006033<em> --- approximated</em>

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<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
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Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

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