The correct answer is: [D]: " y = - 4x − 13 " .
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Explanation:
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All the answer choices given are written in "point-slope format" (also known as "slope-intercept format" — that is: " y = mx + b" .
All of the answer choices given have a slope of "-4" ; that is: "m = -4" .
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The only answer choice with the equation that passes through point
"(-3, 1)" — that is, when "x = -3, y = 1" — is:
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Answer choice: [D]: " y = - 4x − 13 " .
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In the equation: " y = - 4x − 13 " ; when "x = - 3, y = 1" .
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Given: " y = - 4x − 13 " ;
↔ - 4x − 13 = y ;
Plug in "(-3)" for "x" ; and see that "y = 1" ;
-4(-3) − 13 = y ;
12 − 13 = y = -1 ;
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So, when x = -3, y = 1 .
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The correct answer is: [D]: " y = - 4x − 13 " .
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Consider choice: [A]: " y = - 4x + 13 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
-4(-3) + 13 = y ; 12 + 13 = 25 ; NOT "-3" .
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Consider choice: [B]: " y = - 4x + 7 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
-4(-3) + 7 = y ; 12 + 7 = 19 ; NOT "-3" .
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Consider choice: [C]: " y = - 4x − 7 " ;
Substitute "(-3)" for "x" and see if "y = -1" ;
-4(-3) − 7 = y ; 12 − 7 = 9 ; NOT "-3" .
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This leaves us with "Answer choice: [D]: " y = - 4x − 13 " ; the only remaining answer choice; which we have already confirmed is correct; so we do not need to check.
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Hope this helps!
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Put this into ratio form:
20 baskets/ 4 minutes.
This means for every 4 minutes, you can make 20 baskets.
Now solve for 1 minute...how many baskets can you make in one minute.
You can solve this in many ways:
1. Cross Multiply:
20/4 = x/1...20×1= 20 ÷ 4= 5 baskets per minute
2. Simplify- (simpler way to solve)
20 baskets ÷ 4 minutes= 5 baskets in 1 minute
3. Critical Thinking:
how many times can 4 go into 20? 5 times. So there are:
5 baskets per minute
Answer:
Range = [5, ∞)
Step-by-step explanation:
The initial number of snakes is 5 and it is increasing at a high rate so the maximum number is infinite. The population is increasing exponentially according to the equation P = 5(2)^t where t = the number of years.
The weight range for 12-year-old is between 76 and 148 pounds.