Answer:
Vertex is (-4, -18)
Step-by-step explanation:
f(x) = 
Let (h, k) be the vertex
An easy way to find h is to use the formula h = -b/2a
In your case where f(x) =
a = 2 and b = 8
So, h = -8/2(1) = -8/2 = -4
Substitue -4 in for x to find k
k = (
) + 8(-4) - 2
= (16) - 32 - 2
= 16 - 32 - 2
= -18
Vertex is (-4, -18)
Note: Another way to find the vertex is to complete the square, but this can really be difficult in some cases
Given:
The graph of a function
.
To find:
The interval where
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So,
for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So,
for
.
Now,
For
, the graph of h(x) is above the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
Only for the interval
, we get
.
Therefore, the correct option is A.
Answer:
It snowed for 6 days in November
Step-by-step explanation:
Since there are 30 days in November
and 20 goes into 100 five times,
30/5=6, so in november snow fell for 6 days
The double angle formula for the sine is

The right hand side is exactly your expression, where 
So, rewriting the expression from right to left, we have

Answer:
sorry if im wrong
Step-by-step explanation:
no
no
yes
yes