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3 years ago

5. Are the slidutu pun - Complete: 1 = = = 8 It’s asking me to complete 1/2=

Mathematics

1 answer:

meriva3 years ago

5 0

Answer:1/2=2/4=4/8

Step-by-step explanation:It's quite simple if you do 1/2 times 2 you would get 2/4 1*2=2 2*2=4 2/4 same with 2/4 time 2 2*2=4 4*2=8 4/8.

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Solve the equation for x X/2- 4 = x/7 + 1

alexgriva [62]

The answer of this problem is x=14
If you want me to show work tell me on this comment Okay ^^

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2 years ago

Can someone SMART actually help me

lisov135 [29]

The answer is 196/3 pi in^3. All you have to do is multiply 7x7, then you have to multiply that by 1/3 and 4, and you get 65.333333333. Then, you have to turn it into a fraction. You have to multiply 65 by 3, then add one, and you get 196/3 pi in^3.

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3 years ago

Write the equation in slope-intercept form.

professor190 [17]

Y - 11 = 3(x + 4)....distribute thru the parenthesis
y - 11 = 3x + 12....add 11 to both sides
y = 3x + 12 + 11...simplify
y = 3x + 23 <==

4 0

3 years ago

z 5 − z+2 2z+4 =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z

yan [13]

Answer:

The sum of all the possible values for z that satisfy the above equation is -5.

Step-by-step explanation:

The given equation is

$\frac{5}{z}-\frac{2z+4}{z+2}=-3$

We need to find the sum of all the possible values for z that satisfy the above equation.

The given equation can be rewritten as

$\frac{5}{z}-\frac{2(z+2)}{z+2}=-3$

Cancel out common factors.

$\frac{5}{z}-2=-3$

Add 2 on both sides.

$\frac{5}{z}-2+2=-3+2$

$\frac{5}{z}=-1$

$5=-z$

Multiply both sides by -1.

$-5=z$

Only z=-5 satisfy the given equation.

Therefore the sum of all the possible values for z that satisfy the above equation is -5.

8 0

2 years ago

Use the Law of Sines to find the measure of angle J to the nearest degree.

rjkz [21]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$

8 0

3 years ago