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2 years ago

Count the possible combinations of 3 letters chosen from A, B, C, D. The possible combinations of 3 letters are __.

Mathematics

2 answers:

anygoal [31]2 years ago

8 0

Answer:

Step-by-step explanation:

We are given the letters:

We write the possible permutations of 3 letters from the given list:

Because order is not important in a combination we cross out the duplicate pairs:

siniylev [52]2 years ago

6 0

Answer:

Step-by-step explanation:

n! / r!(n-r)!

n = # of total objects

r = # grouped together at a time

4! / 3!(4-3)!

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Please help will give brainliest

Eddi Din [679]

Answer:

-6

Step-by-step explanation:

The equation is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

The y intercept is the value when x = 0

The y value is -6 when the x value is 0

y = -4x+ (-6)

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2 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

Find the difference between 7 1/2 and 2 3/4

NNADVOKAT [17]

Answer:

4 $\frac{3}{4}$ or 4.75

Step-by-step explanation:

first we're going to convert the number into improper fractions.

7 $\frac{1}{2}$ = $\frac{15}{2}$ and 2 $\frac{3}{4}$ = $\frac{11}{4}$

For subtracting it is suitable to adjust both fractions to an equal denominator, so we're going to multiply $\frac{15}{2}$ x2, it'll equal the same number.

So now we have $\frac{30}{4}$ - $\frac{11}{4}$ , 30-11= 19.