Answer:
zero goats and 120 Ilamas to get profit of $15,120
Step-by-step explanation:
Goats: G
Ilamas: l
Explicit constraints:
2G + 5l ≤ 400
100G+ 80l≤ 13,200
Implicit constraints
G≥0
I≥0
P= 84G+ 126l
See attachment for optimal area
substituting coordinats of optimal region in profit equation to get profit
When G= 132, l=0
P=84(132) + 126(0)
P=11,088
When G=0, l=120
P=84(0)+ 126(120)
P = 15120
When G= 100, l=40
P=84(100)+126(40)
P=13440
The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
<h3>What is the solution of equation?</h3>The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.
Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,
For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>
Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
Learn more about the solution of the equation here;