1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enyata [817]
2 years ago
8

Estimate and then solve 8,784 ÷ 61 = ___.

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0

Answer:

8784/61

144#

Mark as a brainlist

You might be interested in
List the domain for the following relation <br><br> (4,1) , (-6,1) , ( 2,7) , (4,-3) , (8,3)
Colt1911 [192]

Answer:

4,-6,2,4,8

Step-by-step explanation:

the domain are the one at the top like the numerator of a fraction

6 0
3 years ago
Consider the initial value problem y″+9y=g(t),y(0)=0,y′(0)=0, where g(t)={t0 if 0 ≤ t &lt;2 if 2 ≤ t &lt; [infinity]. Take the L
AURORKA [14]

Step-by-step explanation:

Calcium carbonate reacts w/stomach acid according to the following chemical equation.

CaCO3+2HCl(aq)-> CaCl2(aq)+H2O(l)+CO2(g)

6 0
3 years ago
find the magnitude of two forces f1 and f2 such that at right-angle to each other, their resultant is √13N. Also, if the two for
serious [3.7K]
This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.

Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6

Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2

The magnitudes of the two forces are 2N and 3N, in no particular order.

5 0
4 years ago
Find the slope between the pair of points: (-4,3) and (6,-2)
ira [324]
Slope is always (y2-y1)/(x2-x1)  in this case:

(-2-3)/(6--4)

-5/10

-1/2
8 0
3 years ago
Read 2 more answers
One kind of hard candy sells for $.89 per kilogram another sells for $1.10 per kilogram how many kilograms of each kind a need t
Furkat [3]

Answer:

20kg of $0.89 candy

10kg of $1.10 candy

Step-by-step explanation:

Candy 1 = 0.89 per kg

Candy 2 = 1.10 per kg

Total kilogram, kg = 30

Let candy 1 = x ; candy 2 = (30 - x) ;

0.89x + 1.10(30 - x) = 0.96(30)

0.89x + 33 - 1.10x = 28.8

0.89x - 1.10x = 28.8 - 33

-0.21x = - 4.2

x = 4.2 / 0.21

x = 20

20kg of $0.89 candy

(30 - x) = (30 - 20) = 10kg

10kg of $1.10 candy

4 0
3 years ago
Other questions:
  • How would you measure the width of a house? Please answer quick! OFFERING 20 POINTS
    15·2 answers
  • What are two lines in the same plane that intersect at right angles?
    6·2 answers
  • A rectangular swimming pool is to be built with an area of 1800 square feet. The owner wants 5-foot wide decks along either side
    9·1 answer
  • Help me ASAP!!<br> This is timed
    10·1 answer
  • Peter needs to wash 20 plates, 30 pieces of silverware, and 10 cups. Then he
    8·2 answers
  • Can someone please help with this?
    10·2 answers
  • Find the surface area of the ball shown. Use 3.14 for pie.
    12·1 answer
  • Find the measure of DF
    15·1 answer
  • The first person to answer this gets brainliest
    9·1 answer
  • What is 2 3/2 equal to?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!