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malfutka [58]
2 years ago
8

Nemos aquarium is filled with 2400 cm of water the base of the aquarium is 20 cm long and 12 cm wide what is the height of the w

ater in Nemo’s aquarium
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
7 0

The answer to this question is 10 cm

In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).

Then you need to divide the volume with the length and width. The equation would be:

Aquarium height= volume / length / width

Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.

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2 years ago
Solve:<br><br> (15/x)+(9x-7)/(x+2)=9
hram777 [196]

Answer:x=3

Step-by-step explanation:

D( x )

x+2 = 0

x = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x = 0

x = 0

x in (-oo:-2) U (-2:0) U (0:+oo)

(9*x-7)/(x+2)+15/x = 9 // - 9

(9*x-7)/(x+2)+15/x-9 = 0

(x*(9*x-7))/(x*(x+2))+(15*(x+2))/(x*(x+2))+(-9*x*(x+2))/(x*(x+2)) = 0

x*(9*x-7)+15*(x+2)-9*x*(x+2) = 0

9*x^2-9*x^2+8*x-18*x+30 = 0

30-10*x = 0

(30-10*x)/(x*(x+2)) = 0

(30-10*x)/(x*(x+2)) = 0 // * x*(x+2)

30-10*x = 0

30-10*x = 0 // - 30

-10*x = -30 // : -10

x = -30/(-10)

x = 3

x = 3

3 0
3 years ago
Use partial fraction expansion to evaluate: LaTeX: \int\frac{x-1}{x^2+3x+2}dx ∫ x − 1 x 2 + 3 x + 2 d x a. LaTeX: -2\ln\left|x+1
ohaa [14]

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8 0
3 years ago
Find the value of x<br> (I need help with both of them pls)
Aleks04 [339]

Answer:

1. x = 21

2. x = 19

Step-by-step explanation:

Since the interior angles of all quadrilaterals add up to 360, all we have to do is add them up and set them equal to 360. Combine like terms and we get

7x + 213 = 360

Which further turns to 7x = 147

So x = 21

For the second problem, it's the same thing

By the end we get 2x + 8 = 46

2x = 38

x = 19

Hope this helps

6 0
2 years ago
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