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3 years ago

GIVING BRAINLIST

Mathematics

2 answers:

Kitty [74]3 years ago

7 0

A function can't have x repeating any of the same number twice for example the first one
So the only right answer is A!

Anton [14]3 years ago

3 0

Answer:

Step-by-step explanation:

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First answer gets brain

Alex787 [66]

$3 \frac{4}{7}m =8 \frac{1}{3} \\ \\\frac{25}{7}m=\frac{25}{3} \\ \\ m= \frac{25}{3}: \frac{25}{7}= \frac{25}{3}* \frac{7}{25}= \frac{7}{3}=2 \frac{1}{3}$

4 0

3 years ago

Read 2 more answers

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago

The pizza shop sells artwork by local artists. For each piece it sells, the shop receives a 15 percent commission. The most expe

Margarita [4]

Answer:

The 15 percent commission is what the shop received.

Step-by-step explanation:

It said that the most expensive piece it ever sold was 225

not that the most money they made is 225

5 0

3 years ago

Dooooooo thissssss plsss

rodikova [14]

The answer is a circle

3 0

3 years ago

What is the surface area of the shape?

Sladkaya [172]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers