Answer: x ≈ 18 ft
Step-by-step explanation:
We will use our trig knowledge to solve this.
The man is standing 10 ft away, but we also need to add the 5 ft shadow as well as that is a point on our triangle.
We can set up a simple trig equation of: tan(50) = x/15
x being the height of the lamppost.
Now we solve.
tan(50) = 1.1918
1.1918 *15 = x
x = 17.876
Now round to the nearest foot.
x ≈ 18 ft
Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
Answer:
225 m2
Step-by-step explanation:
area= side*side
= 15x15
225 m2
F(x) = g(x) for x = 1 and x = 3. Verify that for yourself.
Yes, sqrt of 1815, cannot be rationalized
