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Y_Kistochka [10]

3 years ago

7

Kim bought 4 3/4 yards blue ribbon and 2 1/4 yards yellow ribbon for a craft project. How much more blue ribbon than yellow ribb

on did Kim buy?

1 answer:

Nikolay [14]3 years ago

6 0

She bought 3 more yards

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A group of 15 friends take a trip to a water park. The total price of the trip is $599.85 before any discounts. The total price

Citrus2011 [14]

Answer:10

Step-by-step explanation:

3 0

3 years ago

An arc of length 15ft subtends a central angle 0 in a circle of radios 9ft. Find measure of 0 in degrees

Kisachek [45]

Answer:

95.49°

Step-by-step explanation:

The arc length formula is s = rФ, where r is the radius and Ф is the central angle in radians. Here, r = 9 ft and s = 15 ft. Thus, the central angle Ф is

Ф = (15 ft) / (9 ft) = 5/3 radians, or

5 rad 180°

------- * ---------- = 95.49°

3 π rad

6 0

3 years ago

Sing acts are 5 min long and comedy acts are 3 min long. The show has 12 acts and last 50 min. How many singing acts and how man

ryzh [129]

Answer

so there are 7 singing acts and 5 comedy acts.

Step-by-step explanation:

Let x= number of singing acts.

Let y= number of comedy acts.

We will take x+y=12 as our first equation, as there are 12 shows in total. We will take 5x+3y=50 as our second equation as there are 50 total minutes, and singing acts are 5 mins and comedy acts are 3 mins.

We solve x+y=12

Y=-x+12

We know y=-x+12, so we will substitute that for the y in the second equation.

1. Substitute 5x+3(-x+12)=50

2. Distribute 5x-3x+36=50

3. Solve 2x+36=50

2x=14

X=7

Now that we have found x, we will find y by substitute the x in 5x+3y=50 with the value, 7, that we found for x.

5(7)+3y=50

35+3y=50

3y=15

Y=5

6 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

L( y′+3 y) = L(9 t)

<em>Using Formula Transform of derivatives</em>

<em> L(y¹(t)) = s y⁻(s)-y(0)</em>

<em> By using Laplace transform formula</em>

<em> </em> $L(t) = \frac{1}{S^{2} }$ <em> </em>

<em>Step(ii):-</em>

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

<em> B = 9/3 = 3</em>

Put s = -3 in equation(i)

9 = C(-3)²

<em>C = 1</em>

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

<em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

<u><em>Step(iv):-</em></u>

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

<em>By using inverse Laplace transform</em>

<em></em> $L^{-1} (\frac{1}{s} ) =1$ <em></em>

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

If mMVUW=(4x+6)° and mWUT=(6x+10)°, what is the measure of WUT

FinnZ [79.3K]

As ray UW bisects ( divides the angles into two equal parts )

WUT = WUV

6x - 10° = 4x + 6°

6x - 4x = 6° + 10°

2x = 16°

x = 16° ÷ 2 = 8°

Putting the value of x in the Angle WUT

6 × 8° - 10° = 48° - 10° = 38°

7 0

2 years ago