We know that the ocean floor has a depth of 247 ft, and we also know that the diver is<span> underwater at depth of 138 ft, so its distance from the ocean floor will be:
</span>
ft
<span>
Now, the </span>rock formations rises to a peak 171 to above the ocean floor, so to find <span>how many feet below the top of the rock formations is the diver, we are going to subtract the distance to the driver form the ocean floor from the rock formations height:
</span>
ft
<span>
We can conclude that the diver is 62 feet </span><span>
below the top of the rock formations.</span>
The expression has 3 terms
X = length
2x + 2(x + 105) = 318
2x + 2x + 210 = 318
4x = 108
x = 27
The length is 27 meters long, and the width is 132 meters wide.
It is extremely important to understand the words of the given problem. There are numerous information's of immense importance that are already given in the question. Based on those information's the answer to the question can be easily deduced.
Let us assume the unknown number = x
Then
14x - 34 = 78
14x = 78 + 34
14x = 112
x = 112/14
= 8
So the unknown number in the given question is 8. I hope the procedure is clear to you and you got the answer that you wanted.
Answers and Step-by-step explanations:
16. Yes; we can see that AB || CD, so by definition of alternate angles, angles BAE and CDE are equal. In addition, angles AEB and CED are vertical angles, so by definition, they are congruent. Then by the AA Similarity Theorem, triangles AEB and CED are similar.
17. No; we see that KL = NO and that angles KLJ and NOM are congruent. However, there is no other indication (whether it's same angles or corresponding sides with the same ratio) that we can use to prove the two triangles are similar. So, these triangles are not similar.
18. Yes; we can see that ML || PO, so by definition of corresponding angles, angles NML and NPO are equal. In addition, we can obviously see that angles MNL and PNO are literally the same angle. So by AA Similarity Theorem, triangles MNL and PNO are similar.
Hope this helps!
