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blondinia [14]
3 years ago
13

1. IF the function f(x) = 2(x – 3)2 – 4 is shifted vertically three units up and horizontally

Mathematics
1 answer:
hichkok12 [17]3 years ago
3 0

Answer:

I believe it is 2(x-5)²−1

Step-by-step explanation:

The parentheses represent the horizontal shift. (X-__) is a shift to the right. (X+__) is a shift to the left. The last number of the function is the vertical shift. A negative number is shifting down and a post number is shifting up.

So, if the graph shifts up three units, then you add 3 + -4 to get -1. And if the graph shifts right 2 units, then you subtract 2 from -3 to get -5.

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19) 15 <= 9 + 3x

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9) Second line

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(took me while to type this out lol cause on mobile)

5 0
2 years ago
What is the distance -4 and 7 on a number line?
andreev551 [17]
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3 0
3 years ago
I cant write it on here do pls look at the picture i provided ​
liq [111]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A class of 30 is divided into 2 groups such that the size of the smaller group is 2/3 the size of the larger group. How large is
pogonyaev

Answer:

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6 0
3 years ago
Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t
Alina [70]

Answer:

~150=50e^{-0.01()20}

~p(100)=\$127.7

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week P_{20}=\$150

Marginal price-demand function p'(x)=-0.5e-0.01x

Generally the The Marginal price function is mathematically given by

  p'(x)=-0.5e^{-0.01x}  

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Therefore the equation when the demand is 20 TVs per week at $150 per TV

150=50e^{-0.01()20}

Giving

p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}

Therefore the Price when the demand is 100 TVs per week

p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}

p(100)=\$127.7

7 0
2 years ago
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