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3 years ago

1. IF the function f(x) = 2(x – 3)2 – 4 is shifted vertically three units up and horizontally

Mathematics

1 answer:

hichkok12 [17]3 years ago

3 0

Answer:

I believe it is 2(x-5)²−1

Step-by-step explanation:

The parentheses represent the horizontal shift. (X-__) is a shift to the right. (X+__) is a shift to the left. The last number of the function is the vertical shift. A negative number is shifting down and a post number is shifting up.

So, if the graph shifts up three units, then you add 3 + -4 to get -1. And if the graph shifts right 2 units, then you subtract 2 from -3 to get -5.

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Y and x have a proportional relationship, and y = 24 when x = 16 What is the value of x when y = 36?

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To solve, we need to know by how much y increase to know how much to increase x by:

First step, divide the new value, 36 by the original 24:

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4 years ago

Find the equation of the line that contains the point (3,-4) and is perpendicular to the line x = 5. Write the line in slope-int

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Step-by-step explanation:

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3 years ago

Steve and Abby purchased a set of vases to place on a 12 foot long mantel above their fireplace. They want to place one vase 1/4

Nonamiya [84]

Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

Step-by-step explanation:

You know that lenght of the mantel above their fireplace is 12 feet.

They want to place one vase $\frac{1}{4}$ of the distance from one end of the mantel. This distance in feet is:

$distance_{vase1}=(12feet)(\frac{1}{4})\\\\distance_{vase1}=3feet$

They want to place the other vase $\frac{3}{4}$ of the distance from the same end of the mantel. Therefore, this distance in feet is:

$distance_{vase2}=(12feet)(\frac{3}{4})\\\\distance_{vase2}=\frac{36feet}{4}\\\\distance_{vase2}=9feet$

Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

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3 years ago