Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
The new area will be 320 in²
<em><u>Explanation</u></em>
Lin has a drawing with an area of 20 in² and she increases all sides by a scale factor of 4.
<u>The general rule</u> we need to use here.......
"<em>If the lengths of the sides in a shape are all increased by a scale factor of
, then the area will be increased by a scale factor of
"</em>
Here the sides are increased by a scale factor of 4. So, the area will be increased by a scale factor of 
Thus, the new area will be: 
Answer:
D
Step-by-step explanation:
Answer:
B 1/2
Step-by-step explanation:
The probability of rolling an even number on a fair, six-sided die is 3/6 = 1/2, which results from three of the six possibilities of {1, 2, 3, 4, 5, 6} being even numbers.
B in the answer <span>not correctly written in scientific notation</span>