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Ierofanga [76]
3 years ago
6

STILL GOING BAN ON THEM ANYWAY

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

Answer:

I-

Step-by-step explanation:

Um okay.

yulyashka [42]3 years ago
7 0

Answer:

Ok...

Step-by-step explanation:

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8ftx4ftx5ft what is the diameter
Serggg [28]

Answer:

nothing

Step-by-step explanation:

6 0
2 years ago
A student conducts several random surveys to find out the most preferred lunch option. Each survey was of 60 students. No studen
stira [4]

Answer:

A

C

is the answer

I think soo

5 0
3 years ago
Sharon runs 7/10 mile mile in 6 minutes. How many miles does she run in one minute? In one hour?
Arada [10]

Answer:

7/60 miles in one minute

7 miles in one hour

Step-by-step explanation:

7/10 = 6 minutes

/6        /6

7/10  / 6 =    7/10 * 1/6 =  7/60

B. 7/10 = 6 minutes

     *10         *10

7/10 *  10 =   70/10  = 7 miles

7 miles = 60 minuites

8 0
2 years ago
At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find
Serggg [28]

Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.

A random sample of <em>n</em> = 111 keypads is analyzed.

Then the sampling distribution of \hat p is:

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

P(0.72

                             =P(-1.25

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0
3 years ago
9 friends are lining up. Joe, Susan, John, and Meredith must be beside each other. How many ways can they line up?
ZanzabumX [31]
<h3>Answer:  17,280</h3>

This is one single number slightly over 17 thousand.

You may need to erase the comma when typing the answer in.

=========================================================

Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

You may need to erase the comma when typing the answer in.

-------------

Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

6 0
3 years ago
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