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Alisiya [41]
3 years ago
15

How do you work out the problem 0.37 divided by 5.18

Mathematics
2 answers:
Firlakuza [10]3 years ago
5 0
1/4 or 0.0714285 is the answer.
sasho [114]3 years ago
3 0
I’ll be honest i don’t know how to do it on paper but i would just use like photomath or a calculator
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√(25 - 10 √(3) + 3)<br> (not as a decimal)
nikitadnepr [17]

Answer:

\huge\boxed{\sqrt{25-10\sqrt3+3}=5-\sqrt3}

Step-by-step explanation:

\sqrt{25-10\sqrt3+3}=(*)\\\\25=5^2\\3=(\sqrt3)^2\\10\sqrt3=(2)(5)(\sqrt3)\\\\(*)=\sqrt{5^2-(2)(5)(\sqrt3)+(\sqrt3)^2}\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=\sqrt{(5-\sqrt3)^2}\\\\\text{use}\ \sqrt{a^2}=|a|\\\\=|5-\sqrt3|=5-\sqrt3\\\\^{\text{because}\ 5>\sqrt3\to5-\sqrt3>0}

6 0
3 years ago
Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.
Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (2,−7)and has a slope of −4
Fantom [35]

Answer:

Step-by-step explanation:

What is the equation of the line that passes through the point (2,−7)and has a slope of −4

6 0
2 years ago
5-minute call costs $5.91 and a 10-minute call costs $10.86. what is the rate of change
KatRina [158]

Answer:

0.96 cents

Step-by-step explanation:

3 0
3 years ago
In AJKL, solve for x.
solong [7]

Answer:

x ≈ 66.73

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan27° = \frac{opposite}{adjacent} = \frac{KL}{JK} = \frac{34}{x} ( multiply both sides by x )

x × tan27° = 34 ( divide both sides by tan27° )

x = \frac{34}{tan27} ≈ 66.73 ( to 2 dec. places )

7 0
3 years ago
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